Electric Charges and Fields
NCERT Class 12 Physics Chapter 1
Electric Charges and Fields for Class 12 Physics, JEE and NEET: Coulomb’s law, electric field, field lines, dipoles, flux and Gauss’s law.
13 topics Updated 8 Nov 2026
In the syllabus: JEE Class 12 syllabus, NEET Class 12 syllabus
With your textbook
NCERT Physics Part I (Class 12), Chapter 1 “Electric Charges and Fields”, reprint 2026-27.
Open the official NCERT chapter (PDF, 4.0 MB, ncert.nic.in) (opens in a new tab)
Checked on 19 Oct 2026.
Learn in this order
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Electric charge: positive, negative and charging
Positive and negative charge, charging by rubbing as electron transfer, and how a gold-leaf electroscope works.
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Conductors and insulators
How they differ, free electrons, where charge goes on each, the metal spoon and semiconductors.
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Basic properties of electric charge
Additivity, conservation and quantisation (q = ne), the value of e, and NCERT Examples 1.1, 1.2.
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Coulomb’s law
Statement and formula F = k|qq|/r, ε and k, the vector form, the force in a medium, and solved numericals.
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Forces between multiple charges
Forces between multiple charges as vector sums of Coulomb forces, and NCERT Examples 1.5 and 1.6.
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Electric field
E = F/q and the test charge, the field of a point charge and of many charges, the SI unit, and solved examples.
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Electric field lines
What they show, density and strength, diagrams of simple charges, and why they never cross or form loops.
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Electric flux
Definition, formula Δϕ = EΔS cos θ, the area vector, SI unit N C m, and NCERT Exercises 1.14 and 1.15 solved.
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Electric dipole
Dipole moment p = q × 2a, its electric field on the axis and equator with derivation, and the 1/r fall-off.
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Dipole in a uniform external field
τ = p × E = pE sin θ with derivation, zero net force, and non-uniform fields.
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Continuous charge distribution
Linear, surface and volume charge density with SI units, and the field of a charged ring.
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Gauss’s law
The statement ϕ = q/ε, the Gaussian surface, flux through a cube, and how it differs from Coulomb’s law.
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Applications of Gauss’s law
Derivations of the field of a long charged wire, an infinite plane sheet and a thin charged shell.
Key formulas in this chapter
Electric charge
- like charges repel; unlike charges attract
- glass rubbed with silk: glass +, silk −
- plastic rubbed with fur: plastic −, fur +
- rubbing transfers electrons; total charge unchanged
- charge on n electrons: q = −ne
Conductors and insulators
- conductor: mobile charge carriers; excess charge redistributes on the surface
- insulator: very few mobile carriers; deposited charge stays local
- conductors: metals, human and animal bodies, earth
- insulators: glass, porcelain, plastic, nylon, dry wood
- semiconductor: resistance between the two
Basic properties of electric charge
- Q = q + q + … + q (with signs)
- q = ne, n an integer
- e = 1.6 × 10 C
- 1 C ≈ 6.25 × 10 e
- 1 µC = 10 C; 1 mC = 10 C
Coulomb’s law
- F = (1/4πε) |qq|/r
- 1/4πε ≈ 9 × 10 N m C
- ε = 8.854 × 10 C N m
- F = (1/4πε)(qq/r) r̂, r = r − r
- F = −F
Forces between multiple charges
- F = F + F + … + F
- F = (q/4πε) Σ (q/r) r̂, i = 2 to n
- F = (1/4πε)(qq/r) r̂
- two equal forces F at angle θ: 2F cos(θ/2)
- three charges: F + F + F = 0
Electric field
- E = F/q (q → 0)
- E = (1/4πε) Q/r, along r̂
- F = qE
- E = E + E + … + E
- unit: N C = V m
Electric field lines
- ΔΩ = ΔS/r
- lines per unit area ∝ E
- point charge: lines per unit area ∝ 1/r
- start on +q, end on −q (or at infinity)
- never cross; no closed loops
Electric flux
- Δϕ = E · ΔS = E ΔS cos θ
- ΔS = ΔS n̂ (outward normal on a closed surface)
- ϕ ≈ Σ E · ΔS
- θ = 0: Δϕ = E ΔS; θ = 90°: Δϕ = 0
- unit: N C m
Electric dipole
- p = q × 2a, from −q to q
- axis, r ≫ a: E = 2p/(4πεr), along p
- equator, r ≫ a: E = p/(4πεr), opposite to p
- Eaxis: Eequator = 2: 1 at the same r in the far field
- far field E ∝ 1/r
Dipole in a uniform field
- τ = p × E
- τ = pE sin θ
- uniform field: net force = 0
- U = −pE cos θ (U = 0 at θ = 90°)
- external work θ → θ: pE(cos θ − cos θ)
Continuous charge distribution
- λ = ΔQ/Δl (C/m)
- σ = ΔQ/ΔS (C/m)
- ρ = ΔQ/ΔV (C/m)
- ΔE = k ρΔV/r′, along r̂′
- E ≈ Σ k ρΔV/r′ r̂′
Gauss’s law
- ϕ = q/ε (closed surface, q enclosed)
- point charge at sphere centre: Δϕ = qΔS/(4πεr)
- no charge inside: ϕ = 0
- charge at a cube’s centre: each face q/(6ε)
- q = εϕ
Applications of Gauss’s law
- wire: E = λ/(2πεr)
- sheet: E = σ/(2ε)
- shell, r > R: E = q/(4πεr)
- shell, r < R: E = 0
- atom model, 0 < r < R: E = (Ze/4πε)(1/r − r/R)
More in Physics
- Units and Measurement
- Motion in a Straight Line
- Motion in a Plane
- Laws of Motion
- Work, Energy and Power
- Systems of Particles and Rotational Motion
- Gravitation
- Mechanical Properties of Solids
- Mechanical Properties of Fluids
- Thermal Properties of Matter
- Thermodynamics
- Kinetic Theory
- Oscillations
- Waves
- Electrostatic Potential and Capacitance
- Current Electricity
- Moving Charges and Magnetism
- Magnetism and Matter
- Electromagnetic Induction
- Alternating Current
- Electromagnetic Waves
- Ray Optics and Optical Instruments
- Wave Optics
- Dual Nature of Radiation and Matter
- Atoms
- Nuclei
- Semiconductor Electronics: Materials, Devices and Simple Circuits