Newton’s third law of motion

NCERT Class 11 Physics Chapter 4 Section 4.6

Quick answer

Newton’s third law says that when body A exerts a force on body B, body B exerts an equal and opposite force on body A at the same instant: FAB = −FBA. The two forces act on different bodies, so they never cancel in the motion of either body.

With your textbook

NCERT Physics Part I (Class 11), Chapter 4 “Laws of Motion”, Section 4.6 “Newton’s third law of motion”, pages 56–57.

Open the official NCERT chapter (PDF, 2.1 MB, ncert.nic.in) (opens in a new tab)

Checked against the 2026-27 reprint on .

What is Newton’s third law?

Newton’s third law in NCERT’s words

To every action, there is always an equal and opposite reaction.

NCERT Physics Part I (Class 11), Section 4.6, page 56

In plain words: forces always come in pairs. If body A pushes or pulls body B, then body B pushes or pulls body A at the same instant, with a force of the same size in the opposite direction. Either force can be called the action; the other is then the reaction.

The third law as an equation

Third law

F⃗AB=−F⃗BA\vec F_{AB} = -\vec F_{BA}

Here F⃗AB\vec F_{AB} is the force on A due to B, and F⃗BA\vec F_{BA} is the force on B due to A. The minus sign means the two forces point in opposite directions, and their magnitudes are equal: ∣F⃗AB∣=∣F⃗BA∣|\vec F_{AB}| = |\vec F_{BA}|⁠.

Properties of action-reaction pairs

  • They act on different bodies. One force acts on A and the other on B, so they never cancel in the motion of either body. Two forces can cancel only when they act on the same body. If you treat A and B together as one system, the pair become internal forces that add up to zero, which is why only external forces count in the second law for a system.
  • They are the same type of force. If the action is a gravitational pull, so is the reaction; if the action is a contact push, so is the reaction.
  • They act at the same instant. The reaction does not come after the action, and neither force causes the other.
  • They hold whether the bodies are at rest or moving, and whether they touch (a push, friction) or not (gravity, the pull between two magnets). A pseudo force, used only in an accelerating frame, has no partner, because no body exerts it.

The weight of a book on a table and the normal force from the table are not a third-law pair, even though they are equal and opposite: both act on the book, and they balance because the book is at rest (Newton’s first law of motion). The partner of the book’s weight is the book’s gravitational pull on the Earth, and the partner of the normal force is the book’s push on the table.

Examples

  • Walking. Your foot pushes the ground backward through friction, and the ground pushes your foot forward. That forward force from the ground moves you. On smooth ice the friction is small, so walking is hard.
  • A rocket. The engine pushes hot gases out backward at high speed, and the gases push the rocket forward. A rocket needs no air to push against, so it works in space.
  • Recoil of a gun. The gun pushes the bullet forward, and the bullet pushes the gun backward.
  • Swimming. A swimmer pushes the water backward with the hands and feet, and the water pushes the swimmer forward.

Example 1: Recoil of a gun

In an ideal two-body recoil model, a gun of mass 4 kg fires a bullet of mass 50 g at 400 m s−1 relative to the ground; neglect the momentum of propellant gas. Find the recoil speed of the gun.

Given: m = 0.05 kg (grams converted to kilograms), v = 400 m s−1 and M = 4 kg. Both start at rest, and the gun is free to recoil (no other horizontal force acts on it).

While the bullet moves along the barrel, the gun and the bullet push on each other with equal and opposite forces for the same time, so they get equal and opposite momenta (this is conservation of momentum for the gun and bullet together):

MV=mvV=mvM=0.05×4004=5 m s−1\begin{aligned} M V &= m v \\ V &= \frac{m v}{M} \\ &= \frac{0.05 \times 400}{4} = 5\ \text{m s}^{-1} \end{aligned}

Answer: The gun recoils at 5 m s−1, opposite to the bullet. The forces are equal, but the gun’s mass is 80 times the bullet’s, so its speed is 80 times smaller.

Example 2: Identifying the two partners

A 2 kg book rests on a table; take g = 10 m s. Identify the third-law partner of its weight and of the table’s upward force.

The weight is the Earth’s 20 N downward pull on the book; its partner is the book’s 20 N gravitational pull on the Earth. The table’s 20 N upward push on the book has a different partner: the book’s 20 N downward push on the table.

Answer: the partners act on the Earth and the table respectively. The two 20 N forces acting on the book balance, but they are not each other’s third-law partners.

Example 3: Equal forces, unequal accelerations

Two skaters of masses 50 kg and 80 kg push each other on smooth horizontal ice with a constant force of 40 N for 0.5 s, starting from rest. Find their accelerations and speeds after the push.

Each experiences a 40 N force in the opposite direction to the other. Their accelerations are 40/50 = 0.8 m s and 40/80 = 0.5 m s, so their speeds become 0.4 m s and 0.25 m s. Each receives an impulse of magnitude 40 × 0.5 = 20 N s.

Answer: accelerations 0.8 and 0.5 m s and speeds 0.4 and 0.25 m s, in opposite directions. Equal interaction forces give equal and opposite changes of momentum, not equal accelerations.

Common mistakes to avoid

Common mistake

The horse-and-cart paradox

“The cart pulls the horse back as hard as the horse pulls the cart forward, so the forces cancel and nothing can move.” This is wrong, because the two forces act on different bodies. To decide whether the cart moves, look only at the forces on the cart: the horse’s pull forward and friction backward. The cart speeds up when the pull is larger than the friction. The horse speeds up because the ground pushes its hooves forward harder than the cart pulls it back.

Common mistake

Thinking that the larger body exerts the larger force

When a truck hits a small car, or the Earth pulls an apple, the two forces are equal in size. Only the effects differ: by Newton’s second law of motion, the same force gives a more massive body a smaller acceleration. An apple of mass 0.1 kg is pulled by the Earth with 0.1 × 9.8 = 0.98 N, and it pulls the Earth with 0.98 N too. Taking the Earth’s mass as 6.0 × 1024 kg, the Earth’s acceleration is only about 1.6 × 10−25 m s−2.

Quick revision summary

  • Forces always come in pairs: when A pushes or pulls B, B pushes or pulls A.
  • The two forces are equal in size, opposite in direction, of the same type and simultaneous.
  • They act on different bodies, so they never cancel in the motion of either body; for the system A + B they are internal forces that add to zero.
  • Equal forces can give very different accelerations: the lighter body accelerates more.
  • Walking, swimming, rockets and the recoil of a gun are all third-law effects.

Formula sheet

  • FAB = −FBA
  • a = F/m for each body
  • M V = m v (recoil, both start at rest)

Questions students ask

Newton’s third law, together with the second law, gives the law of conservation of momentum. When two bodies interact and no external force acts, they exert equal and opposite forces on each other for the same time, so they receive equal and opposite impulses: ΔpA = −ΔpB. The momentum one body gains, the other loses, so their total momentum stays constant; NCERT Section 4.7 (pages 57–58) extends this to any number of bodies.

What is the difference between balanced forces and action-reaction forces?

Balanced forces act on the same body and add up to zero, so they cancel; an action-reaction pair acts on two different bodies, so its two forces never cancel in the motion of either body. For a bucket hanging at rest from a rope, the rope’s pull and the bucket’s weight are balanced forces, while the partner of the rope’s pull on the bucket is the bucket’s pull on the rope. Balanced forces can be of different types and need not exist together (cut the rope and the weight remains), but the two forces of a third-law pair are always of the same type and exist together.

How does Newton’s third law apply to a person in a lift?

A person standing in a lift pushes down on the floor and the floor pushes up on the person with a force of the same size N at every instant: these two forces are a third-law pair. When the lift accelerates upward at a, N grows to m(g + a) for a person of mass m, as the second law gives, but the push of the person on the floor grows with it, so the pair stays equal and opposite. The person’s weight mg and N are not a pair, because both act on the person; that is why they can differ while the lift accelerates.

Practice questions

Try each question first, then open the answer to check your working.

  1. Q1. A person of mass 60 kg stands on frictionless ice and throws a 2 kg ball horizontally at 6 m s−1 relative to the ground. With what speed does the person move back?

    Show answerHide answer

    The person and the ball push on each other with equal and opposite forces for the same time, so their momenta are equal and opposite: 60 V = 2 × 6, which gives V = 12/60 = 0.2 m s−1, opposite to the ball.

  2. Q2. A book rests on a table. Are its weight and the normal force from the table an action-reaction pair?

    Show answerHide answer

    No. Both forces act on the book, so they cannot be a third-law pair; they are equal because the book is in equilibrium. The reaction to the weight is the book’s gravitational pull on the Earth, and the reaction to the normal force is the book’s push on the table.

  3. Q3. In a collision, a car of mass 1000 kg and a truck of mass 5000 kg push on each other with a force of 5 × 104 N. Ignoring all other forces during the collision, find the acceleration of each.

    Show answerHide answer

    By the third law, each feels a force of 5 × 104 N. Car: a = 5 × 104/1000 = 50 m s−2. Truck: a = 5 × 104/5000 = 10 m s−2. The forces are equal, but the lighter car gets five times the acceleration.

Sources and review

Written by
TopicLamp Editorial Team.
Checked by
TopicLamp Review Team.
NCERT source
NCERT, Physics Part I (Class 11), reprint 2026-27. Chapter 4 “Laws of Motion”, Section 4.6 “Newton’s third law of motion”, pages 56–57. Checked on . Official chapter PDF on ncert.nic.in (opens in a new tab) (2.1 MB).
Dates
First published Checked and updated
Corrections
  • : Specified recoil and throwing reference frames; added worked examples for force partners and equal forces on unequal masses.

Report a mistake on this page How pages are written, reviewed and corrected

Topics in Laws of Motion

  1. Aristotle’s fallacy

    NCERT Section 4.2 11 min read

  2. The law of inertia

    NCERT Section 4.3 14 min read

  3. Newton’s first law of motion

    NCERT Section 4.4 9 min read

  4. Newton’s second law of motion

    NCERT Section 4.5 13 min read

  5. Newton’s third law of motion

    NCERT Section 4.6 You are reading this topic

  6. Conservation of momentum

    NCERT Section 4.7 14 min read

  7. Equilibrium of a particle

    NCERT Section 4.8 12 min read

  8. Friction and other common forces

    NCERT Section 4.9 19 min read

  9. Dynamics of circular motion

    NCERT Section 4.10 15 min read

  10. Solving problems in mechanics

    NCERT Section 4.11 14 min read