Redox Reactions
NCERT Class 11 Chemistry Chapter 7
Redox Reactions for Class 11 Chemistry, JEE and NEET: oxidation and reduction, oxidation numbers, balancing redox equations and electrode processes.
4 topics Updated 8 Nov 2026
In the syllabus: JEE Class 11 syllabus, NEET Class 11 syllabus
With your textbook
NCERT Chemistry Part II (Class 11), Chapter 7 “Redox Reactions”, reprint 2026-27.
Open the official NCERT chapter (PDF, 1.9 MB, ncert.nic.in) (opens in a new tab)
Checked on 19 Oct 2026.
Learn in this order
-
Classical idea of redox reactions
Classical definitions by oxygen and hydrogen, oxidising and reducing agents, NCERT Problem 7.1 solved.
-
Redox reactions as electron transfer
Oxidation as loss of electrons, half reactions and the Zn, Cu, Ag order, with examples.
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Oxidation number
How to find it with the rules, Stock notation, types of redox reactions, balancing and titrations, solved.
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Redox reactions and electrode processes
Redox couples, salt bridge, anode and cathode signs and the E° table, solved.
Key formulas in this chapter
Classical idea of oxidation and reduction
- Oxidation: + O or electronegative element; − H or electropositive element
- Reduction: − O or electronegative element; + H or electropositive element
- Oxidising agent is reduced; reducing agent is oxidised
Redox reactions as electron transfer
- Oxidation = loss of electrons; reduction = gain of electrons
- Oxidising agent accepts electrons; reducing agent donates electrons
- Electrons lost = electrons gained
- Electron-releasing tendency: Zn > Cu > Ag
Oxidation number
- Sum of oxidation numbers = 0 (compound) or the charge (ion)
- Oxidation = increase in oxidation number; reduction = decrease
- Common maximum: group number (1, 2) or group number − 10 (13–17); O and F are exceptions
- Total increase in oxidation number = total decrease
Redox reactions and electrode processes
- E⊖ of H+/H2 = 0.00 V by convention
- Higher E⊖: stronger oxidising agent; lower E⊖: stronger reducing agent
- E⊖(cell) = E⊖(cathode) − E⊖(anode); Daniell cell 1.10 V
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