More practice questions

  1. Q4. The same force F stretches two springs, one stiff (k1) and one soft (k2 < k1). Which stores more energy?

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    The stretch is F/k, so the energy is 12k(F/k)2\tfrac{1}{2}k(F/k)^{2}, that is F2/(2k). For the same force, the softer spring (smaller k) stretches more and stores more energy. (For the same stretch, it is the other way round: the stiffer spring stores more, 12kx2\tfrac{1}{2}kx^{2}.)

  2. Q5. A 1 kg block is dropped from 0.5 m above the top of a vertical spring of spring constant 1000 N m. Find the greatest compression of the spring. Take g = 9.8 m s−2.

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    At the greatest compression x the block is momentarily at rest. It has fallen 0.5 + x, so the gravitational potential energy lost equals the spring energy gained:

    1×9.8×(0.5+x)=12×1000×x2\begin{aligned} &1 \times 9.8 \times (0.5 + x) \\ &= \tfrac{1}{2} \times 1000 \times x^{2} \end{aligned} 500x2−9.8x−4.9=0500x^{2} - 9.8x - 4.9 = 0 x=9.8+9.82+4×500×4.91000=9.8+99.481000≈0.109 m\begin{aligned} x &= \frac{9.8 + \sqrt{9.8^{2} + 4 \times 500 \times 4.9}}{1000} \\ &= \frac{9.8 + 99.48}{1000} \approx 0.109\ \text{m} \end{aligned}

    about 10.9 cm.

  3. Q6. A spring stores 2 J of energy when stretched by 4 cm. How much energy does it store when stretched by 6 cm, and what is its spring constant?

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    k = 2V/x2 = 4/0.0016, that is 2500 N m. At 6 cm the energy is 12(2500)(0.06)2\tfrac{1}{2}(2500)(0.06)^{2}⁠, that is 4.5 J (it goes as x2: (6/4)2 × 2 = 4.5).