More practice questions

  1. Q4. A truck of mass 4000 kg and a car of mass 1000 kg have the same kinetic energy. Find the ratio of their speeds and the ratio of their momenta.

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    Equal kinetic energy means that mv2 is the same for both, so the ratio of speeds is 1000/4000=1/2\sqrt{1000/4000} = 1/2: the truck moves at half the car’s speed. Momentum is 2mK\sqrt{2mK}, so the ratio of momenta is 4000/1000=2\sqrt{4000/1000} = 2: the truck has twice the momentum.

  2. Q5. The speed of a body increases by 20%. By what percentage does its kinetic energy increase?

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    The kinetic energy is multiplied by 1.22 = 1.44, an increase of 44%.

  3. Q6. A body has momentum 20 kg m s and kinetic energy 50 J. Find its mass and speed.

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    From K = p2/2m, the mass is p2/2K:

    m=4002×50=4 kgm = \frac{400}{2 \times 50} = 4\ \text{kg}

    and the speed is p/m = 20/4, that is 5 m s.

  4. Q7. A 60 kg runner is moving at 5 m s. A 0.06 kg ball is moving at 30 m s. Which has more kinetic energy, and which has more momentum?

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    For the runner, K = ½ × 60 × 5, which is 750 J, and p = 60 × 5, which is 300 kg m s. For the ball, K = ½ × 0.06 × 30, which is 27 J, and p = 0.06 × 30, which is 1.8 kg m s. The runner has more of both.