More practice questions

  1. Q4. A non-uniform bar 2 m long hangs at rest, horizontal, from two light strings tied to its ends. The left string makes 36.9° with the vertical and the right string 53.1°. Find the distance d of the bar’s centre of gravity from its left end. (NCERT Exercise 6.8.)

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    Let the tensions be T1 (left) and T2 (right); sin 36.9° ≈ 0.6, cos 36.9° ≈ 0.8, and the reverse for 53.1°.

    Horizontal forces: 0.6T1 = 0.8T2, so T1 = (4/3)T2.

    Moments about the centre of gravity (the horizontal parts of the tensions act along the bar, so they have no moment): 0.8T1 × d = 0.6T2 × (2 − d). With T1 = (4/3)T2: (16/15)d = 0.6(2 − d), so (5/3)d = 1.2 and d = 0.72 m.

  2. Q5. A uniform beam 4 m long and of weight 200 N rests on supports at its two ends. A load of 300 N hangs 1 m from the left end. Find the force on each support.

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    Moments about the left support: Rright × 4 = 200 × 2 + 300 × 1 = 700, so Rright = 175 N. Forces: Rleft = 500 − 175 = 325 N. The support nearer the load carries more.

  3. Q6. A uniform plank 6 m long and of weight 300 N lies on a flat roof with 2 m of it sticking out beyond the edge. How far beyond the edge can a person of weight 600 N walk before the plank starts to tip?

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    On the point of tipping, the plank pivots on the edge of the roof and the roof pushes only there. The plank’s weight acts at its middle, 3 m from either end, which is 1 m back from the edge. Moments about the edge: 600 × x = 300 × 1, so x = 0.5 m. Beyond 0.5 m the plank tips.