Q4. Compare g at a height of RE/2 above the surface with g at a depth of RE/2 below it.
Height: g/(1.5) = 4g/9, about 0.444g. Depth: g(1 − ½) = 0.5g. So g is larger at the depth (0.5g against about 0.44g).
Q5. A body weighs 72 N on the Earth’s surface. What does it weigh at a height of RE/2?
W = 72/(1 + ½) = 72/2.25 = 32 N.
Q6. What would a 50 kg body weigh at the centre of the Earth, treated as uniform? What would its mass be?
Its weight would be zero, because g = 0 at the centre; its mass would still be 50 kg.