More practice questions

  1. Q5. Two groups compete for a board. The first wins with probability 0.6 and the second with 0.4. A new product is introduced with probability 0.7 if the first group wins and 0.3 if the second wins. A new product was introduced. Find the probability that the second group introduced it (NCERT Exercise 13.3, Q9, page 432).

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    The product paths are 0.6 × 0.7 = 0.42 and 0.4 × 0.3 = 0.12, so the probability is 0.12/0.54 = 2/9.

  2. Q6. A girl throws a die. On 5 or 6 she tosses a coin three times; on 1, 2, 3 or 4 she tosses it once. Assume a fair die and independent fair coin tosses. She gets exactly one head. Find the probability that she threw 1, 2, 3 or 4 (NCERT Exercise 13.3, Q10, page 432).

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    P(one head | 1–4) = 1/2 and P(one head | 5 or 6) = 3/8. The paths are (2/3)(1/2) = 1/3 and (1/3)(3/8) = 1/8, so the probability is (1/3)/(1/3 + 1/8) = 8/11.

  3. Q7. Operators A, B and C make 1%, 5% and 7% defective items and are on the job 50%, 30% and 20% of the time. Assume equal output rates, so the time shares also give the fractions of items produced. A defective item is selected at random. Find the probability that A produced it (NCERT Exercise 13.3, Q11, page 432).

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    The defective paths are 0.005, 0.015 and 0.014, which add up to 0.034. So the probability is 0.005/0.034 = 5/34.

  4. Q8. A uniformly random card is lost from a pack of 52. Two cards drawn from the rest are both diamonds. Find the probability that the lost card is a diamond (NCERT Exercise 13.3, Q12, page 432).

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    If the lost card is a diamond (probability 13/52), two diamonds come from 12 of 51 cards; if not (39/52), from 13 of 51. The chances are in the ratio (1/4)(12 × 11) : (3/4)(13 × 12) = 33 : 117, so the probability is 33/150 = 11/50.

  5. Q9. Three boxes hold two gold coins, two silver coins, and one of each. A box is chosen at random and a coin taken out is gold. Find the probability that the other coin in the box is gold (NCERT Example 17, pages 426–427).

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    The other coin is gold only for the gold–gold box. The gold paths are (1/3)(1) and (1/3)(1/2), so the probability is (1/3)/(1/2) = 2/3, not 1/2: the gold–gold box is twice as likely to give a gold coin.

  6. Q10. Beyond the NCERT text (JEE): in NCERT Example 18, the person is tested a second time and is again positive. Assume the two results are independent for a person with HIV and for a person without it. Find the new probability of HIV.

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    The two-positive paths are 0.001 × 0.92 = 0.00081 and 0.999 × 0.012 = 0.0000999, so the probability is 0.00081/0.0009099 = 300/337, about 0.89. The first answer, about 0.083, has become the prior for the second test.

  7. Q11. 5% of men and 0.25% of women have grey hair, and there are equal numbers of men and women. A grey-haired person is chosen at random. Find the probability that the person is male (NCERT Miscellaneous Exercise on Chapter 13, Q3, page 435).

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    (1/2)(0.05)/[(1/2)(0.05) + (1/2)(0.0025)] = 0.05/0.0525 = 20/21.

  8. Q12. In this hypothetical probability model, the chance of a heart attack is 40%. A yoga course cuts the risk by 30% relative to the original risk and a drug by 25% relative to it, and a patient chooses one of the two with equal probability. A patient has a heart attack. Find the probability that the patient did the yoga course (NCERT Miscellaneous Exercise on Chapter 13, Q7, page 436).

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    The risks are 0.4 × 0.7 = 0.28 and 0.4 × 0.75 = 0.30, each with prior 1/2, so the probability is 0.28/0.58 = 14/29.

  9. Q13. Bag I has 3 red and 4 black balls, and Bag II has 4 red and 5 black. One ball is moved from Bag I to Bag II, and then a ball drawn from Bag II is red. Find the probability that the moved ball was black (NCERT Miscellaneous Exercise on Chapter 13, Q10, page 436).

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    If the moved ball was red (3/7), Bag II has 5 red of 10; if black (4/7), 4 red of 10. So the probability is (4/7)(4/10)/[(3/7)(5/10) + (4/7)(4/10)] = 16/31.