Q5. Find ∫(ax2 + bx + c) dx and ∫(2x2 + ex) dx (NCERT Exercise 7.1, Q8 and Q9, page 234).
ax3/3 + bx2/2 + cx + C, and (2/3)x3 + ex + C.
Q6. Find ∫(√x − 1/√x)2 dx (NCERT Exercise 7.1, Q10, page 234).
The square is x − 2 + 1/x, so the integral is x2/2 − 2x + log |x| + C.
Q7. Find ∫(x3 − x2 + x − 1)/(x − 1) dx (NCERT Exercise 7.1, Q13, page 234).
The top factorises as (x − 1)(x2 + 1), so the integrand is x2 + 1 (for x ≠ 1) and the integral is x3/3 + x + C.
Q8. Find ∫(1 − x)√x dx and ∫√x(3x2 + 2x + 3) dx (NCERT Exercise 7.1, Q14 and Q15, pages 234–235).
∫(x1/2 − x3/2) dx = (2/3)x3/2 − (2/5)x5/2 + C. ∫(3x5/2 + 2x3/2 + 3x1/2) dx = (6/7)x7/2 + (4/5)x5/2 + 2x3/2 + C.
Q9. Find ∫(2x − 3 cos x + ex) dx and ∫(2x2 − 3 sin x + 5√x) dx (NCERT Exercise 7.1, Q16 and Q17, page 235).
x2 − 3 sin x + ex + C, and (2/3)x3 + 3 cos x + (10/3)x3/2 + C.
Q10. Find the curve y = F(x) through (1, 2) whose slope at every point is 3x2 + 1.
F(x) = x3 + x + C, and F(1) = 2 gives 1 + 1 + C = 2, so C = 0: y = x3 + x.
Q11. Find F with F′(x) = 1/x for x ≠ 0, F(1) = 0 and F(−1) = 2.
Beyond the NCERT text: x ≠ 0 is two intervals, and each takes its own constant. F(x) = log x for x > 0 and F(x) = log (−x) + 2 for x < 0; no single log |x| + C meets both conditions.