More practice questions

  1. Q5. Examine the continuity of (a) f(x) = x − 5; (b) f(x) = 1/(x − 5), x ≠ 5; (c) f(x) = (x2 − 25)/(x + 5), x ≠ −5; (d) f(x) = |x − 5| (NCERT Exercise 5.1, Q3, page 116).

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    (a) is a polynomial and (b), (c) are rational functions, continuous on their domains; (d) is |·| composed with x − 5. All four are continuous functions. (In (c), −5 is not in the domain, so it is not a point of discontinuity.)

  2. Q6. Is f(x) = x3 − 3 for x ≤ 2 and x2 + 1 for x > 2 continuous? (NCERT Exercise 5.1, Q11, page 116)

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    At 2, f(2) and the left-hand limit are 8 − 3 = 5, and the right-hand limit is 4 + 1 = 5. Elsewhere each piece is a polynomial. So there is no point of discontinuity.

  3. Q7. Find the points of discontinuity of f(x) = x/|x| for x < 0 and −1 for x ≥ 0 (NCERT Exercise 5.1, Q9, page 116).

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    For x < 0, |x| = −x, so x/|x| = x/(−x) = −1. So f(x) = −1 for every x: a constant function, with no point of discontinuity.

  4. Q8. Discuss the continuity of f(x) = x2 sin (1/x) for x ≠ 0 and f(0) = 0 (NCERT Exercise 5.1, Q24, page 117).

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    For x ≠ 0 it is a product and composite of continuous functions. At 0: −x2 ≤ x2 sin (1/x) ≤ x2, and both bounds tend to 0, so the limit is 0 = f(0). So f is continuous for all real x.

  5. Q9. Find all points of discontinuity of f(x) = sin x/x for x < 0 and x + 1 for x ≥ 0 (NCERT Exercise 5.1, Q23, page 117).

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    At 0, the left-hand limit is lim sin x/x = 1 and the right-hand limit and f(0) are 0 + 1 = 1. Elsewhere the pieces are continuous. There is no point of discontinuity.

  6. Q10. Discuss the continuity of the cosine, cosecant, secant and cotangent functions (NCERT Exercise 5.1, Q22, page 117).

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    Each is a quotient of continuous functions, continuous wherever its denominator is not 0: cosec x = 1/sin x for x ≠ nπ, sec x = 1/cos x for x ≠ (2n + 1)π/2, and cot x = cos x/sin x for x ≠ nπ, with n an integer. cos x itself is continuous for every real x.

  7. Q11. Show that |cos x| and sin |x| are continuous functions (NCERT Exercise 5.1, Q32 and Q33, page 118).

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    |cos x| is |·| composed with cos, and sin |x| is sin composed with |·|. Both inner and outer functions are continuous everywhere, so by NCERT Theorem 2 both composites are continuous.