More practice questions

3. Q3. Classify CH₃CH=CHCH₂Br and C₆H₅CH(CH₃)Br as allylic, benzylic, vinylic or aryl, and as 1°, 2° or 3°.

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   CH₃CH=CHCH₂Br: Br is on an sp³ carbon next to the C=C, carrying one other carbon: a 1° allylic halide. C₆H₅CH(CH₃)Br: Br is on an sp³ carbon next to the ring, carrying the ring carbon and a methyl group: a 2° benzylic halide (NCERT pages 160–161; reasoned).

4. Q4. Classify 3-bromocyclohexene and 1-bromocyclohexene.

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   3-Bromocyclohexene: Br is on the ring carbon next to the C=C, which is sp³ and bonded to two carbons, so it is a 2° allylic halide. 1-Bromocyclohexene: Br is on a C=C carbon, so it is vinylic (NCERT pages 160–161; reasoned).