Q4. Write the formulas for (i) amminebromidochloridonitrito-N-platinate(II), (ii) dichloridobis(ethane-1,2-diamine)platinum(IV) nitrate, (iii) iron(III) hexacyanidoferrate(II). (NCERT Intext Question 5.1, parts (iv)–(vi).)
(i) [Pt(NH3)BrCl(NO2)]−: Pt +2 with Br−, Cl− and NO2− gives 2 − 3 = −1. (ii) [PtCl2(en)2](NO3)2: Pt +4 with two Cl− gives +2, so two nitrates. (iii) Fe4[Fe(CN)6]3 (NCERT answers, page 140).
Q5. Write the IUPAC names of (i) [Co(NH3)6]Cl3, (ii) K3[Fe(CN)6], (iii) [Pt(NH3)2Cl(NH2CH3)]Cl. (NCERT Intext Question 5.2, parts (i), (iii) and (vi).)
(i) Hexaamminecobalt(III) chloride, (ii) potassium hexacyanidoferrate(III), (iii) diamminechlorido(methanamine)platinum(II) chloride (NCERT answers, page 140).
Q6. In iron(III) hexacyanidoferrate(II), Fe4[Fe(CN)6]3, why does the name give iron two different oxidation states?
The four iron atoms outside the brackets are Fe3+ cations, 4 × (+3) = +12. Each complex anion [Fe(CN)6]4− holds iron +2 (x − 6 = −4), and three of them give −12. The cation is named first with its oxidation state, and the anion’s iron takes the Latin -ate form, ferrate(II) (reasoned).
Q7. Using IUPAC norms, write the formulas of (i) tetrahydroxidozincate(II), (ii) diamminedichloridoplatinum(II), (iii) hexaamminecobalt(III) sulphate, (iv) potassium tri(oxalato)chromate(III), (v) hexaammineplatinum(IV), (vi) tetrabromidocuprate(II). (NCERT Exercise 5.6, parts (i), (iii) and (vi)–(ix).)
(i) [Zn(OH)4]2−, (ii) [Pt(NH3)2Cl2], neutral, so no charge and no -ate, (iii) [Co(NH3)6]2(SO4)3, (iv) K3[Cr(C2O4)3], (v) [Pt(NH3)6]4+, (vi) [CuBr4]2−. In (iii), two cations of charge +3 balance three sulphates, 2 × 3 = 3 × 2. NCERT’s tri(oxalato) in (iv) is the trioxalato of its Example 5.3(b): oxalato contains no number, so it needs no tris and no parentheses (reasoned).
Q8. Using IUPAC norms, write the systematic names of (i) [Ti(H2O)6]3+, (ii) [Co(NH3)4Cl(NO2)]Cl, (iii) [Mn(H2O)6]2+, (iv) [NiCl4]2−, (v) [Ni(NH3)6]Cl2, (vi) [Co(en)3]3+, (vii) [Ni(CO)4]. (NCERT Exercise 5.7, parts (iii)–(ix).)
(i) Hexaaquatitanium(III) ion, (ii) tetraamminechloridonitrito-N-cobalt(III) chloride, (iii) hexaaquamanganese(II) ion, (iv) tetrachloridonickelate(II) ion, (v) hexaamminenickel(II) chloride, (vi) tris(ethane-1,2-diamine)cobalt(III) ion, (vii) tetracarbonylnickel(0) (reasoned; (vii) as in NCERT Example 5.2(e), page 124).